Tuesday, February 10, 2015

Instantaneous Rate of Change - Royce Mizoguchi

A. A short ranged rocket is launched off of a launch ramp at  75.5 feet high . Its height is recorded every 2 seconds. The equation of the parabola is (-2(x-3.5)^2)+ 100

B. As a engineer you need to be able to track data accurately to see where you can make changes to the design. Also you need to be able to find the instantaneous rate of change in order to, add propulsion at any point in flight needed.

C, D, E.
Instantaneous rate of change is the change in height. The slope of 4 seconds turns to be into negative feet because it is slowly declining. By 6 seconds the slope was at -10 feet per second. 

F. I noticed that the at 4 seconds was the rockets peak and when it was at 6 seconds it slowly started to decline down. By 8 seconds it was lower than when it originally started.  

G. 95.5-75.5/ 6-2 = 10 FT Per second. 
H. In my experiment I was able to identify the average height of the rocket per second. At the 1 second on the secant line, the slope of the secant line is 10 which is the IRC. Therefore we have the average height the rocket will go up per second which is 10 Feet per second. 

6 comments:

  1. Good explanation, but you are missing a table with the set input and output values.

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  2. Hello Royce;

    I do agree with Paris, your data looks missing. This table is important to clear your report. Thanks.


    Mishal

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  3. Its on the first picture

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  4. Very interesting. I find point f very interesting, where the reader gets a very good idea on the changes the rocket experiences through time.

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  5. Good job Royce. Despite the fact that you included many info on the first picture and it looks a bit disorganized, you did a great job

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  6. royce,

    great intro! it made me want to read more! your table and graph in the first part look good. however, as the post goes on, i noticed that your secant line calculations are not done correctly. you want to do calculations around the same point, not different points. so, if you wanted to know what is happening at t = 2 seconds, your should have used points from 4 to 2, 6 to 2, and 8 to 2. your calculations show random points on the graph that aren't really related to the final IRC calculation. let me know if you don't understand where the mistake is here.

    other than that, you picked a fun topic!

    professor little

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