Blog # 2
Asma Aljarbou
Math-211
2/11/15
Asma Aljarbou
Math-211
2/11/15
a. Find a real world application OR
design your own experimental application relating to rates of change. (in the
blog folder you will find plenty of examples to get you started)
I choose to do the relationship
of the world population growth rate (%) over time (years).
worldometers.info
b. Write a narrative or synopsis
explaining your application/experiment and include a question. (for example, what is the velocity of the
snowball at exactly 2 seconds? Or how can I find the velocity of the baseball
at exactly 3 seconds?)
For the growth rate
variation over time “years”, I will try to show you how as times goes, the growth
rate decrease and I will be using ARC to find the slope of the tangent line. My
proper question will be:
·
How can I find growth
rate percentage at the year of 2005?
c. Create a table of values for the data
that you have recorded from your application/experiment.
Years, Y
|
1950
|
1975
|
2005
|
2035
|
2065
|
2095
|
Growth Rate% R, F(y)
|
1.78
|
1.77
|
1.19
|
0.66
|
0.29
|
0.11
|
d. Graph the points using the data from
your table of values (connect the dots).
This graph shows the
relationship between population growth rate and time in terms of years and I
took this graph from the website I used to find my experiment, but I chose some
point to make my graph smaller you can see my graph in part F.
e. Calculate the slope (ARC) of at least three secant lines originating
from the same point on your graph to three different points on your graph
To find the slope ARC the original
formula state that [ ARC = f(b)-f(a) / b-a ]
I want to know what happen in the year
2005 so I will use the points of (2005, 2095) (2005, 2065) (2005, 2035)
ARC=0.11-1.19/2095-2005= -0.012 %/Yr
ARC=0.29-1.19/2065-2005= -0.015 %/Yr
ARC=0.66-1.19/2035-2005= -0.0176 %/Yr
I notice that as I get closer to point
(2005,1.19) the smaller ARC I have, and hopefully I will end up with a
limited number very close to the slope of 2005.
f. Sketch an approximation of a tangent line that passes
though the same point (P)
Tangent line at X = 2005 is a line that
touches the graph at that point and parallel. As you can see the pink line in the graph represent the tangent line to
the function that pass through the point P= (2005,1.1)
g. Choose a second point (Q) on the tangent line, and
calculate the slope of the line (PQ).
The slope is “rise/run”
or “Y2-Y1/X2-X1” and for my point (PQ) P=(2005,1.1), Q=(1975,1.6)
The Instantaneous
rate of change IRC = Slope =
1.6-1.1/1975-2005 = - 0.0166 %/Yr
And since my calculations of slope from
part d are getting smaller and smaller, this shows that the slope of the secant
is getting closer and closer to the tangent line at the point where time = 2005 and if i continue in taking point that closer to X =2005 I will end up having tangent line = secant line.
h.
my experiment conclude the rise of population growth over the run of years, and In my experiment I was able to find the average population growth rate per year -0.016, and at the year 1950 the secant line has a slope of -0.016. In my experiment in the years of 1950 the population growth rate was in its highest with 1.9% where it is expected to be the lowest with 0.2% in 2095.
Hi Asma;
ReplyDeleteworld population growth is very important deal nowadays. A lot of reports and researches handled this growing issue. I hope that your expectations are true and they find a way to control population growth. Unfortunately, the plant resource will suffer shortage soon at current rate of growth. Thanks again
Reem
asma,
ReplyDeleteyour post was very interesting! i didn't realize that researchers were projecting that there will be fewer people on the planet in the future. =( you did a good job and i really like that you showed the comparison of your secant line with your tangent line to add more proof to why you know your IRC calculation is correct.
nice job!
professor little